Consider the following array declaration in ‘C’ language:int array[] = {2, 3, 4, 5};What will be the output of the following statement?printf("%d", 2[array]);a)4b)3c)2d)5Correct answer is option 'A'. Can you explain this answer?

Question

Consider the following array declaration in &lsquo;C&rsquo; language:int array[] = {2, 3, 4, 5};What will be the output of the following statement?printf("%d", 2[array]);a)4b)3c)2d)5Correct answer is option 'A'. Can you explain this answer?

Answer

An array is defined as the collection of similar types of data items stored at contiguous memory locations. Arrays are the derived data type in C programming language which can store the primitive type of data such as int, char, double, float, etc. C array is beneficial if you have to store similar elements.

int array[] = {2, 3, 4, 5}; This array storage be like,

The above array at index I can be accessed by, a[i], i[a], *(a+i) or *(i+a) all the above representations all are equal and gives the i th index value.

printf(%d', 2[array]); So, it gives the 2nd index value. i.e 4.

Hence the correct answer is 4.

Answer

Explanation:

Accessing array elements:
- In C language, array elements can be accessed using the index of the element within square brackets.
- The first element of an array has an index of 0, the second element has an index of 1, and so on.

Given array declaration:
- int array[] = {2, 3, 4, 5};
- The array 'array' contains elements {2, 3, 4, 5}.

Understanding the statement:
- In the statement printf('%d', 2[array]);, 2[array] is equivalent to array[2].
- array[2] means accessing the element at index 2 in the array 'array'.

Output:
- The element at index 2 in the array 'array' is 4.
- Therefore, the output of the statement printf('%d', 2[array]); will be 4.

Therefore, the correct option is option 'A' which is 4.

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